2021-10-26 15:00:07 +05:30
|
|
|
/*
|
|
|
|
|
A program to calculate the Aliquot Sum of a number.
|
|
|
|
|
The aliquot sum of a number n, is the sum of all the proper divisors of n apart from n itself
|
|
|
|
|
For example, for the number 6
|
|
|
|
|
The divisors are 1, 2, 3 (we don't consider 6), so its aliquot sum is 1 + 2 + 3 = 6
|
|
|
|
|
1 is the only number whose aliquot sum is 0 (since its only divisor is 1 and aliquot sum of a number couldn't have itself)
|
|
|
|
|
For all prime numbers, the aliquot sum is 1, since their only divisor apart from themselves is 1
|
|
|
|
|
Article on Aliquot Sum: https://en.wikipedia.org/wiki/Aliquot_sum
|
|
|
|
|
*/
|
|
|
|
|
|
|
|
|
|
/**
|
|
|
|
|
* @param {Number} input The number whose aliquot sum you want to calculate
|
|
|
|
|
*/
|
2023-10-03 23:08:19 +02:00
|
|
|
function aliquotSum(input) {
|
2021-10-26 15:00:07 +05:30
|
|
|
// input can't be negative
|
|
|
|
|
if (input < 0) throw new TypeError('Input cannot be Negative')
|
|
|
|
|
|
|
|
|
|
// input can't be a decimal
|
2023-10-03 23:08:19 +02:00
|
|
|
if (Math.floor(input) !== input)
|
|
|
|
|
throw new TypeError('Input cannot be a Decimal')
|
2021-10-26 15:00:07 +05:30
|
|
|
|
|
|
|
|
// Dealing with 1, which isn't a prime
|
|
|
|
|
if (input === 1) return 0
|
|
|
|
|
|
|
|
|
|
let sum = 0
|
2023-10-03 23:08:19 +02:00
|
|
|
for (let i = 1; i <= input / 2; i++) {
|
2021-10-26 15:00:07 +05:30
|
|
|
if (input % i === 0) sum += i
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
return sum
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
export { aliquotSum }
|